非圓齒輪二次開(kāi)發(fā)

lijun1226

畫(huà)齒廓，為什么最高點(diǎn)不在齒頂高那里。感覺(jué)不對(duì)。大家能看看我的程序嗎？Dim i As Integer
0 N. v  O. ?/ D7 G! c  }" cReDim x0(18)
+ R6 H  o9 V, F0 ]# AReDim y0(18)

Dim k0 As Integer
  y$ n! q, c) C3 ^3 JReDim p0(18)
ReDim q0(18)

Dim h0 As Integer
ReDim p00(18)
# ?% t9 ?1 A& x' O2 i4 sReDim q00(18)
5 x' j; p* G, c/ F# M

u = Sqr((Da / Db) ^ 2 - 1)
g = u / 14


0 Z0 ?4 y( q! @$ k3 C* Sxx = 0.5 * Da * Sin(Tan(f) - f)
( I* l  V/ _$ lyy = 0.5 * Da * Cos(Tan(f) - f)
# y1 _/ S& Z* Y# w5 v; x9 {
% B3 s; f: \) N' c. u$ I

3 ]; f) O. q8 N- p
s = pi * m / 2
inva = Tan(a) - a
/ n+ ~2 r) o# P  S; n: }8 A  Ysb = Cos(a) * (s + m * z * inva)
j = 2 * sb / Db

t = 0

For i = 1 To 14

! L5 h2 y0 M( V0 U% k' ]9 OIf t <= u Then
$ z, o) `+ n4 d3 t) I8 ^
) I5 n3 t' E; y- A- ~x0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t)
3 K7 Y9 k4 I# Q0 T( xy0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t)

p00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)
% w' e8 e* g8 {, S& Y4 h1 v/ E3 Tq00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)
2 H# K& P1 Y5 V, a" o: U
+ {! X4 I# ]4 r( S  ^$ n, xt = t + g

& O* w" Z  |5 g2 A, v/ v3 y  Q1 z* [p0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j)
End If
4 o1 h( X8 b7 E5 }( w% ZNext i

Part.SetPickMode
' g: k% v, P) Gxx = 0
yy = 0.5 * Df
2 I$ h' W: H/ d+ `/ ^. vXx1 = xx * Cos(j) + yy * Sin(j)
+ s% F) o1 R1 [( t. g+ xYy1 = xx * Sin(j) + yy * Cos(j)
2 y4 d5 E: L, V0 O+ n$ A" V# O
+ x- |0 [6 \( @# ?p000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)
, Z5 s: @; B6 G* kq000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0)
" O# _4 `* @* |: I+ @! v
7 ?3 v5 N- [" M! G2 U, ~, ^

Part.SketchSpline 13, 0.001 * x0(1), 0.001 * y0(1), 0
4 }4 b7 A6 c8 d$ H2 q8 r" tPart.SketchSpline 12, 0.001 * x0(2), 0.001 * y0(2), 0
! p5 d" }# T( x3 j* ZPart.SketchSpline 11, 0.001 * x0(3), 0.001 * y0(3), 0
Part.SketchSpline 10, 0.001 * x0(4), 0.001 * y0(4), 0
Part.SketchSpline 9, 0.001 * x0(5), 0.001 * y0(5), 0
; k, l* U+ j0 S7 a1 M2 K0 W9 r# VPart.SketchSpline 8, 0.001 * x0(6), 0.001 * y0(6), 0
Part.SketchSpline 7, 0.001 * x0(7), 0.001 * y0(7), 0
1 A/ @$ a" L& z; i9 [" X; [
) y7 L) p2 |" UPart.SketchSpline 6, 0.001 * x0(8), 0.001 * y0(8), 0
Part.SketchSpline 5, 0.001 * x0(9), 0.001 * y0(9), 0
Part.SketchSpline 4, 0.001 * x0(10), 0.001 * y0(10), 0
Part.SketchSpline 3, 0.001 * x0(11), 0.001 * y0(11), 0
( r  ~* ^2 a* l& b/ e% pPart.SketchSpline 2, 0.001 * x0(12), 0.001 * y0(12), 0
8 g0 f. n& C' W  mPart.SketchSpline 1, 0.001 * x0(13), 0.001 * y0(13), 0
Part.SketchSpline 0, 0.001 * x0(14), 0.001 * y0(14), 0


Part.SketchSpline 13, 0.001 * p0(1), 0.001 * q0(1), 0
$ f6 K/ m) M- Y: GPart.SketchSpline 12, 0.001 * p0(2), 0.001 * q0(2), 0
1 K3 I; g+ l: JPart.SketchSpline 11, 0.001 * p0(3), 0.001 * q0(3), 0
8 [( U" k3 O- s3 _Part.SketchSpline 10, 0.001 * p0(4), 0.001 * q0(4), 0
; c6 t; Y  O' n% z* `* Y& ^* k9 aPart.SketchSpline 9, 0.001 * p0(5), 0.001 * q0(5), 0
Part.SketchSpline 8, 0.001 * p0(6), 0.001 * q0(6), 0
) [! J7 [4 p% c4 MPart.SketchSpline 7, 0.001 * p0(7), 0.001 * q0(7), 0
; ]5 C* Y8 r5 F# C0 z
9 t8 Q) h* v1 s: N/ ?Part.SketchSpline 6, 0.001 * p0(8), 0.001 * q0(8), 0
Part.SketchSpline 5, 0.001 * p0(9), 0.001 * q0(9), 0
Part.SketchSpline 4, 0.001 * p0(10), 0.001 * q0(10), 0
Part.SketchSpline 3, 0.001 * p0(11), 0.001 * q0(11), 0
Part.SketchSpline 2, 0.001 * p0(12), 0.001 * q0(12), 0
0 L9 s& n' ]2 x0 G8 M6 [Part.SketchSpline 1, 0.001 * p0(13), 0.001 * q0(13), 0
0 d7 A( |; O, ^9 H0 l4 ?" a9 ]$ {Part.SketchSpline 0, 0.001 * p0(14), 0.001 * q0(14), 0
0 j% s4 S& j" Q. a1 G; ~3 G3 q1 k  u

George_W4TBo

是solidworks的二開(kāi)嗎，真費(fèi)勁哥都比較擯棄，這是最近做的一個(gè)單邊連續(xù)，單邊步進(jìn)機(jī)構(gòu)的其中一對(duì)非圓齒輪，在家里所以圖不多，有空再更新，歡迎交流