非圓齒輪二次開(kāi)發(fā)

lijun1226

畫(huà)齒廓，為什么最高點(diǎn)不在齒頂高那里。感覺(jué)不對(duì)。大家能看看我的程序嗎？Dim i As Integer
ReDim x0(18)
% [5 s( u  e0 R9 m  Q) _ReDim y0(18)

  z  s$ \5 S- S, ?) H5 Q8 K. ZDim k0 As Integer
7 l% _  Q& u# l( K( f' K# v! tReDim p0(18)
ReDim q0(18)

Dim h0 As Integer
ReDim p00(18)
ReDim q00(18)


( e8 S8 a+ \8 yu = Sqr((Da / Db) ^ 2 - 1)
6 e7 k* U8 e' D' s0 Wg = u / 14
$ Y. `5 i+ k: r1 e) L9 _6 G* z1 }/ ~
- Q& |' y3 p; E  ^! P
  M% ^4 s$ M' V7 e7 r* _xx = 0.5 * Da * Sin(Tan(f) - f)
yy = 0.5 * Da * Cos(Tan(f) - f)

0 v1 U, y5 ~- U( D; ^2 {% X, g
. J3 U0 `. y$ N  e* M+ a# f& s

. [/ U: k) x- c4 B4 ~s = pi * m / 2
, ]& ?9 E; \' i( R' k7 f3 Yinva = Tan(a) - a
sb = Cos(a) * (s + m * z * inva)
! `% d' I# p% mj = 2 * sb / Db

& j0 e% F2 l5 g+ t" n! p! \t = 0

. b* g8 c3 Z2 i6 D5 ^For i = 1 To 14
2 N9 c3 y. F# R" F
% g9 q# g6 `2 {If t <= u Then

x0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t)
y0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t)

( Y+ {$ ?7 D' V7 Y. tp00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)
q00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)
0 Q0 h/ j/ n" e: ]3 J( I3 ]
; a1 w0 \/ a! j; [" Y' i4 r* k% q4 it = t + g

# e9 `" g5 u7 y/ m$ s! tp0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j)
% M, P3 {) r* b0 E7 L% `End If
Next i

Part.SetPickMode
2 s6 ?, ^! Q- B$ V9 ^& a4 H8 dxx = 0
+ a+ D, a3 _: W7 qyy = 0.5 * Df
Xx1 = xx * Cos(j) + yy * Sin(j)
0 f- a6 ~- X8 {/ @( `; J; TYy1 = xx * Sin(j) + yy * Cos(j)

p000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)
2 G% _: g* ~, i8 Pq000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0)
5 }$ l  m; P7 q, j; }2 Z( p7 v
/ [" m: r$ o3 ?8 F5 h. }( I) I, P0 v
0 G: T2 m# W# s- l# o2 z
Part.SketchSpline 13, 0.001 * x0(1), 0.001 * y0(1), 0
5 X8 d; s, f9 o& S3 T2 VPart.SketchSpline 12, 0.001 * x0(2), 0.001 * y0(2), 0
Part.SketchSpline 11, 0.001 * x0(3), 0.001 * y0(3), 0
9 ~" h6 u' `% j3 ?' oPart.SketchSpline 10, 0.001 * x0(4), 0.001 * y0(4), 0
Part.SketchSpline 9, 0.001 * x0(5), 0.001 * y0(5), 0
Part.SketchSpline 8, 0.001 * x0(6), 0.001 * y0(6), 0
3 h' Y  Q. D$ ]- p* B2 pPart.SketchSpline 7, 0.001 * x0(7), 0.001 * y0(7), 0
) Q. z' T6 t3 x, W0 f
Part.SketchSpline 6, 0.001 * x0(8), 0.001 * y0(8), 0
Part.SketchSpline 5, 0.001 * x0(9), 0.001 * y0(9), 0
2 u! M* x8 A) [7 P! K* nPart.SketchSpline 4, 0.001 * x0(10), 0.001 * y0(10), 0
Part.SketchSpline 3, 0.001 * x0(11), 0.001 * y0(11), 0
Part.SketchSpline 2, 0.001 * x0(12), 0.001 * y0(12), 0
Part.SketchSpline 1, 0.001 * x0(13), 0.001 * y0(13), 0
1 v( {/ I) k, j7 vPart.SketchSpline 0, 0.001 * x0(14), 0.001 * y0(14), 0


Part.SketchSpline 13, 0.001 * p0(1), 0.001 * q0(1), 0
Part.SketchSpline 12, 0.001 * p0(2), 0.001 * q0(2), 0
7 l, C' v1 W$ S& P3 D3 ~2 ePart.SketchSpline 11, 0.001 * p0(3), 0.001 * q0(3), 0
% a, w/ B" e. JPart.SketchSpline 10, 0.001 * p0(4), 0.001 * q0(4), 0
Part.SketchSpline 9, 0.001 * p0(5), 0.001 * q0(5), 0
Part.SketchSpline 8, 0.001 * p0(6), 0.001 * q0(6), 0
# a5 N3 c2 N* R& O2 vPart.SketchSpline 7, 0.001 * p0(7), 0.001 * q0(7), 0

Part.SketchSpline 6, 0.001 * p0(8), 0.001 * q0(8), 0
) J* v: |% n! ?Part.SketchSpline 5, 0.001 * p0(9), 0.001 * q0(9), 0
Part.SketchSpline 4, 0.001 * p0(10), 0.001 * q0(10), 0
% T' J6 Q# b  v: u; B' \# q0 H% f$ tPart.SketchSpline 3, 0.001 * p0(11), 0.001 * q0(11), 0
# Y1 \! S; w  |/ v4 K/ r  o  qPart.SketchSpline 2, 0.001 * p0(12), 0.001 * q0(12), 0
2 x" }9 R1 H0 {3 N! RPart.SketchSpline 1, 0.001 * p0(13), 0.001 * q0(13), 0
$ Y9 r$ q" ?, O! _  w: g7 F/ gPart.SketchSpline 0, 0.001 * p0(14), 0.001 * q0(14), 0

- d1 O8 |9 Y0 L; B8 K# r5 n

George_W4TBo

是solidworks的二開(kāi)嗎，真費(fèi)勁哥都比較擯棄，這是最近做的一個(gè)單邊連續(xù)，單邊步進(jìn)機(jī)構(gòu)的其中一對(duì)非圓齒輪，在家里所以圖不多，有空再更新，歡迎交流